[QST] is define CUTE_LEFT_UNARY_OP right？

[shanliang1992]

in include/cute/numeric/integral_constant.hpp

#define CUTE_LEFT_UNARY_OP(OP)                                                                                         \
    template <auto t> CUTE_HOST_DEVICE constexpr C<(OP t)> operator OP(C<t>) { return {}; }

CUTE_LEFT_UNARY_OP(+);
CUTE_LEFT_UNARY_OP(-);
CUTE_LEFT_UNARY_OP(~);
CUTE_LEFT_UNARY_OP(!);
CUTE_LEFT_UNARY_OP(*);

how to use <* t> in template?

constexpr auto mul_five = C<* 5>{};
is not correct.

[hwu36]

@thakkarV

[ccecka]

This is not a multiplication operator, this is a unary dereference operator.

Although it is not likely used (yet), pointers can be constexpr as well.

#include <cute/tensor.hpp>
using namespace cute;

int main()
{
  static constexpr int a[] = {4,3,2,1};
  auto cute_ptr = C<a>{};
  auto cute_val = *cute_ptr;
  static_assert(cute_val == 4);
}